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Mad Scientists Science and Mathematics discussion-- theories, arguments, citations, proofs and pudding.

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  #1   Add magixx to your ignore list  
Old 2008-01-24, 06:17
magixx magixx is offline
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Default Chemistry Help

Yes I realize that there is Mad Scientist but I figured that I would get quicker replies here and hopefully 5% of those replies will be useful.

Anyway, My first question is:

In a titration experiment, a student neutralized 25.0 mL of sulphuric acid solution using 36.8 mL of 0.125 mol / L sodium hydroxide solution. Calculate the concentration of the sulphuric acid solution. Now I got a final answer of 0.093mol/L which seems weird. My Calculations Are:
n=cv
n(NaOH)=0.0368L*0.125mol/L=4.6E-3
Since balanced part of equation is H2SO4 +2NaOH that means that we calculated for 2 NaOH, so its actually 2.3E-3 mol for H2SO4. Then use c=n/v:
=2.3E-3/0.025L
and get 0.092 mol/L which seems odd to me.

Now,

What mass of lithium was reacted with an excess of 0.250 mol/L HCl(aq) to form 1.35 L of hydrogen gas collected by the downward displacement of water measured at 97.4 kPa and 26.0 °C?

This is the one I'm having most trouble with, Now I know the balanced equation does not need any coefficients, and that since you are in water you need to subtract water vapour pressure to get like a total of 94.04kPa. But what next? Would you just use PV=nRT?, plus I dont get why they tell you the concentration of HCl.
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  #2   Add H a r o l d to your ignore list  
Old 2008-01-24, 06:20
H a r o l d H a r o l d is offline
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Default Re: Chemistry Help

If nuclearrabbit was still here he could have helped you.
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  #3   Add Molosh to your ignore list  
Old 2008-01-24, 06:29
Molosh Molosh is offline
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» BC, Canada «
Default Re: Chemistry Help

Fuck your homework.
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  #4   Add danmega to your ignore list  
Old 2008-01-24, 07:10
danmega danmega is offline
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Kingston, Canada Send a message via MSN to danmega
Angry Re: Chemistry Help

Oh yeah? Well fuck your couch.
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  #5   Add Beholder to your ignore list  
Old 2008-01-24, 07:27
Beholder Beholder is offline
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Penn State Pa
Default Re: Chemistry Help

I don't have chem anymore because I graduated High school.


hahhahaahahahahahhahaahah
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  #6   Add DonJabronyo to your ignore list  
Old 2008-01-24, 12:17
DonJabronyo DonJabronyo is offline
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Shithole
Default Re: Chemistry Help

Quote:
Originally Posted by magixx View Post
Yes I realize that there is Mad Scientist but I figured that I would get quicker replies here and hopefully 5% of those replies will be useful.

Anyway, My first question is:

In a titration experiment, a student neutralized 25.0 mL of sulphuric acid solution using 36.8 mL of 0.125 mol / L sodium hydroxide solution. Calculate the concentration of the sulphuric acid solution. Now I got a final answer of 0.093mol/L which seems weird. My Calculations Are:
n=cv
n(NaOH)=0.0368L*0.125mol/L=4.6E-3
Since balanced part of equation is H2SO4 +2NaOH that means that we calculated for 2 NaOH, so its actually 2.3E-3 mol for H2SO4. Then use c=n/v:
=2.3E-3/0.025L
and get 0.092 mol/L which seems odd to me.

Now,

What mass of lithium was reacted with an excess of 0.250 mol/L HCl(aq) to form 1.35 L of hydrogen gas collected by the downward displacement of water measured at 97.4 kPa and 26.0 °C?

This is the one I'm having most trouble with, Now I know the balanced equation does not need any coefficients, and that since you are in water you need to subtract water vapour pressure to get like a total of 94.04kPa. But what next? Would you just use PV=nRT?, plus I dont get why they tell you the concentration of HCl.
PV=nrt the hydrogen gas to get the moles of hydrogen. Number of moles of hydrogen = same number of moles of HCl. I assume it's a lithium salt you're using so moles of lithium is also the same as the moles of hydrogen. Check the balanced equation of Li + HCl to make sure it's a 1:1 reaction. Thus, just multiply the moles of hydrogen with the molecular mass of lithium. Too tired to look for my periodic table lol
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  #7   Add Galbador to your ignore list  
Old 2008-01-24, 12:18
Galbador Galbador is online now
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London, England
Default Re: Chemistry Help

Quote:
Originally Posted by DonJabronyo View Post
PV=nrt the hydrogen gas to get the moles of hydrogen. Number of moles of hydrogen = same number of moles of HCl. I assume it's a lithium salt you're using so moles of lithium is also the same as the moles of hydrogen. Thus, just multiply the moles of hydrogen with the molecular mass of lithium. Too tired to look for my periodic table lol
This.
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  #8   Add DonJabronyo to your ignore list  
Old 2008-01-24, 12:26
DonJabronyo DonJabronyo is offline
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Shithole
Default Re: Chemistry Help

Quote:
Originally Posted by magixx View Post
Yes I realize that there is Mad Scientist but I figured that I would get quicker replies here and hopefully 5% of those replies will be useful.

Anyway, My first question is:

In a titration experiment, a student neutralized 25.0 mL of sulphuric acid solution using 36.8 mL of 0.125 mol / L sodium hydroxide solution. Calculate the concentration of the sulphuric acid solution. Now I got a final answer of 0.093mol/L which seems weird. My Calculations Are:
n=cv
n(NaOH)=0.0368L*0.125mol/L=4.6E-3
Since balanced part of equation is H2SO4 +2NaOH that means that we calculated for 2 NaOH, so its actually 2.3E-3 mol for H2SO4. Then use c=n/v:
=2.3E-3/0.025L
and get 0.092 mol/L which seems odd to me.

Now,

What mass of lithium was reacted with an excess of 0.250 mol/L HCl(aq) to form 1.35 L of hydrogen gas collected by the downward displacement of water measured at 97.4 kPa and 26.0 °C?

This is the one I'm having most trouble with, Now I know the balanced equation does not need any coefficients, and that since you are in water you need to subtract water vapour pressure to get like a total of 94.04kPa. But what next? Would you just use PV=nRT?, plus I dont get why they tell you the concentration of HCl.
WTF is 4.6E-3?
Anyway you need two moles of NaOH for each H2SO4 right? Just get the number of moles of NaOH by multiplying 0.0368 to 0.125 and then multiply by two to get the moles of H2SO4 that you oxidized. Divide that by 25mL but first convert it to litres to get the initial concentration of the sulfuric acid solution.

Last edited by DonJabronyo : 2008-01-24 at 12:39.
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  #9   Add brad davis to your ignore list  
Old 2008-01-24, 13:27
brad davis brad davis is offline
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the other side
Red face Re: Chemistry Help

i cant provide you with any help here.
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  #10   Add Bates23 to your ignore list  
Old 2008-01-24, 13:32
Bates23 Bates23 is offline
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A cave, because I'm a hermit. Send a message via AIM to Bates23 Send a message via MSN to Bates23
Thumbs up Re: Chemistry Help

Murder/suicide.
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This thread continued for 2 pages in the real archive, 15 posts total - only page 1 survived here.
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