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| Mad Scientists Science and Mathematics discussion-- theories, arguments, citations, proofs and pudding. |
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#1
 2009-01-08, 20:59
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Particle collision question involving a photon
A deuteron (deuterium nuclei, basically the bound state of a proton and neutron) is struck by a photon and dissociates into a proton and a neutron, which both move off in the same direction, with respective speeds Vp and Vn (which are both a lot less than the speed of light). Calculate the minimum photon energy required given that the binding energy B = 2.224589 MeV.
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#2
 2009-01-11, 00:49
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xarf 
Regular
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Re: Particle collision question involving a photon
Ephoton = Binding Energy + Kinetic Energy of the particles?
Shit, what about conservation of momentum?
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#3
 2009-01-11, 09:29
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Re: Particle collision question involving a photon
Quote:
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Originally Posted by xarf
Ephoton = Binding Energy + Kinetic Energy of the particles?
Shit, what about conservation of momentum?
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Yeah, that was exactly my thinking.
I have the solution now, i'll post it up in a couple of days. It's quite a nice problem.
Hint: First show that the minimum energy is when Vp = Vn assuming Mp = Mn.
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