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| Mad Scientists Science and Mathematics discussion-- theories, arguments, citations, proofs and pudding. |
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#1
 2008-09-29, 13:41
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derivative question
Can somebody show me what
lim e^tanx
x->pi/2+
is please?
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#2
 2008-09-29, 16:37
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bobfish 
Regular
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Re: derivative question
Yes..
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#3
 2008-09-29, 16:46
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Re: derivative question
Sorry the title meant to say limit question.
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#4
 2008-10-01, 03:29
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Re: derivative question
So no one knows the answer to this question?
Lifejunkie where are you! lol
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#5
 2008-10-01, 03:46
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Shadout Mapes 
Regular
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Re: derivative question
just move the limit inside the exponent:
exp( lim(x-> pi/2+) tanx)
As you move from x = pi to x = pi/2 (this is what the + means right? it's been a while, i might be going in the wrong direction) tanx goes to -infinity. so now:
lim (x-> -infinity) e^x
i hope that simplifies the problem sufficiently
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#6
 2008-10-01, 15:08
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bobfish 
Regular
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Re: derivative question
Pi/2 has no tangent. Division by 0.
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#7
 2008-10-02, 06:09
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Shadout Mapes 
Regular
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Re: derivative question
Quote:
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Originally Posted by bobfish
Pi/2 has no tangent. Division by 0.
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Which would be the purpose of taking the limit. Although it is an important distinction that a one-sided limit is usually necessary in the case where the denominator approaches zero for the limit to be defined.
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#8
 2008-10-02, 20:11
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SelfAdjoint 
Regular
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Re: derivative question
Since the exponential function is a continuous function, you can take the limit inside the exponent. Which gives you a divergent limit. Problem solved; the limit doesn't exist. If the limit approaches from the other side of pi/2, the limit is zero.
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